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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] can the Muenchian method do this?
Hi, I would like to select a distinct value based on a sibling. I know that the Muenchian method is used to select distinct values, but can I give it another variable to look at? Here is my xml: <songlist> <song> <Artist>J-Live</Artist> <Genre>Rap</Genre> </song> <song> <Artist>Phish</Artist> <Genre>Rock</Genre> </song> <song> <Artist>J-Live</Artist> <Genre>Rap</Genre> </song> <song> <Artist>Jay-Z</Artist> <Genre>Rap</Genre> </song> </songlist> I would like to select all the artists whose Genre is 'Rap' but not have duplicates. So my return set would be 'J-Live, Jay-Z' Is this possible? I know I can do this with recursion, but obviously the Muenchian method is preferred. Thanks, Dan
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