Finding the position of an ancestor

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Subject: Finding the position of an ancestor
From: Nicholas Orr <nick@xxxxxxxxxxx>
Date: Tue, 20 Dec 2005 13:40:07 +1100

I was wondering if someone can help me work out a position issue I'm struggling with.

I've got some XML that has is in it :

<FMPReport> <File> <ScriptCatalog> <Script> <StepList> <Step> ... </Step> <Step> ... </Step> <Step> ... </Step> <Step id="1" name="Perform Script" enable="True"> <Value> <DisplayCalculation> <Chunk type="FieldRef"> <Field id="32867" name="cPref Server Temp Folder" table="gPrefs" />

Then in the xslt I run a for each loop

<xsl:for-each select="/FMPReport/File/ descendant::Chunk[@type='FieldRef']/Field"> <xsl:call-template name="RESULTSET" /> </xsl:for-each>

which works fine, and I can get the data I need. I grab the name from the Step using :

<xsl:value-of select="ancestor::Step[1]/@name" />

But how do I grab the step number? For example I want to know that this is step 4 in this script, by counting how many <Step> elements there are in the current <Script> element. I thought it would just be :

<xsl:value-of select="ancestor::Step[1]/position ()"/>

But that doesn't work, and gives me a parsing error. Am I maybe going about the whole thing wrong?

Thanks,
Nick

Current Thread
Finding the position of an ancestor Nicholas Orr - 20 Dec 2005 02:40:02 -0000 <= Kamal Bhatt - 20 Dec 2005 02:52:50 -0000 Nicholas Orr - 20 Dec 2005 04:10:57 -0000 Kamal Bhatt - 20 Dec 2005 04:21:12 -0000 <Possible follow-ups> Xia Li - 20 Dec 2005 20:19:52 -0000

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RE: stylesheet functions or n, Michael Kay	Thread	Re: Finding the position of a, Kamal Bhatt
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