RE: for-each checking count of nodes

Try 

position() != last()

Ryan Puddephatt
Web Developer
TFX Group
1 Michaelson Square
Livingston
West Lothian
Scotand
EH54 7DP
 
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-----Original Message-----
From: Mark Williams [mailto:mark@xxxxxxxxxxx] 
Sent: 14 December 2005 12:38
To: XSL-List
Subject:  for-each checking count of nodes

Hi,

My XML looks something like:

<?xml version="1.0" ?>
<Root>
<DATA>
<Table Name ="clients">
<data>
<name>Jones</name>
<dob> 19/11/1962</dob>
</data>
<data>
<name>Davies</name>
<dob> 10/12/1963</dob>
</data>
</Table>
</Root>

In the xsl I need to output a line after I have outputted each client's
data.

I have tried to do it this way:

<xsl:for-each select="DATA/Table[@Name='clients']/data">
<fo:block font-family="Helvetica" font-size="10pt"
space-after="0.05pt"><xsl:value-of select="name" /></fo:block>
<fo:block font-family="Helvetica" font-size="10pt"
space-after="0.05pt"><xsl:value-of select="dob" /></fo:block>
<xsl:if test="position() &lt;
count(DATA/Table[@Name='clients']/data/name)">
<fo:block white-space-collapse="false" font-family="Helvetica"
font-size="10pt" space-after="0.05pt">___________________</fo:block>
</xsl:if>
</xsl:for-each>

Can anyone please tell me what is wrong with my xsl:if statement as the
line is never outputted.

Many thanks,

Mark Williams