Re: XML fragment as a param ?
>>>>> "Fraser" == Fraser Goffin <goffinf@xxxxxxxxxxx> writes: Fraser> Colin, thanks for the pointer. I assume you mean the Fraser> technique that was discussed in relation to the document Fraser> function (note: I am using XSLT 1.0 rather than 2). I Fraser> tried this (in XML Spy for now), but got the error Fraser> 'Error in function doument; Could not find external Fraser> entity' Fraser> Is this perhaps related to to the use of data: not being Fraser> supported Correct. Fraser> I haven't come across data: before. I thought that the Fraser> document() function accepted a resolvable URI as a Fraser> parameter, so does the use of data: provide a sort of Fraser> resolver itself then ? No. data is a standard URI scheme. But which URI schemes are supported is processor dependent. So you will need to implement a resolver that handles the data URI scheme, for this to work. (Or get someone else to do it - I can supply Eiffel code for such a resolver, if that helps). -- Colin Adams Preston Lancashire
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