Re: sorted for-each: preceding::sibling is not in sort

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Subject: Re: sorted for-each: preceding::sibling is not in sort order
From: Ferdinand Soethe <xsl-list@xxxxxxxxxx>
Date: Sun, 13 Nov 2005 17:59:09 +0100

Thank you all for your insights. At least now I know that didn't miss
anything.

Michael wrote:

> XSLT 2.0 allows you to use xsl:sequence
> instead of xsl:copy-of, so you can construct a variable whose value is a
> sequence of nodes (node references) without making copies of the nodes.

Wouldn't I once again have the problem with
preceding::sibling when they are references?

--
Ferdinand Soethe

Current Thread
sorted for-each: preceding::sibling is not in sort order Ferdinand Soethe - 13 Nov 2005 08:44:04 -0000 Ragulf Pickaxe - 13 Nov 2005 15:30:52 -0000 David Carlisle - 13 Nov 2005 15:36:46 -0000 Michael Kay - 13 Nov 2005 16:11:23 -0000 Ferdinand Soethe - 13 Nov 2005 16:59:19 -0000 <= Michael Kay - 13 Nov 2005 18:24:49 -0000

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