Re: merging the contents of consecutive
could do that lots of different ways how about <xsl:template match="overview[info]"> <info><xsl:apply-templates select="info"/></info> </xsl:template> do whatever you want with info in an info template your previous template should probably have been something like <xsl:template match="overview/info[following-sibling::*[local-name()='info']"> <info><xsl:value-of select="."/><xsl:text> </xsl:text><xsl:vaue-of select="following-sibling::*[local-name()='info']"/></nfo> </xsl:template> and then <xsl:template match="overview/info"/> to get other infos out of the picture I am however 99% certain that this is not the way you should do it , and instead use the other method (there is always a possiblity I don't know some requirement you have that makes this reasonable) given this slight hint of uncertainty I have used a rather bad xpath to get what should have been a lot easier to get, see former example. On 10/18/05, Annmarie Rubin (anrubin) <anrubin@xxxxxxxxx> wrote: > Thanks for the tip, Michael. > > I want to generate a single element to replace two consecutive info > elements that are children of an overview element and have the same name > (and concatenate their contents.) There will be no more than one pair > of these info elements in each overview element. I don't want to > generate a single element containing all duplicate elements. > > For example, this code finds the info element that is a child of an > overview element and whose next following sibling is also an info > element. > > <xsl:template match="overview/info[following-sibling::*[self::info]]" > > > > At this point, I'm stuck. How do I concatenate both elements? > > thanks, > > Ann Marie
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