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RE: rogue xmlns="" in output xhtml
Subject: RE: rogue xmlns="" in output xhtml
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Sat, 15 Oct 2005 20:17:15 +0100
|
 > I'm
> guessing it has to do with the fact that I added the XTHML
> namespace to the
> code thus:
>
> <html xmlns="http://www.w3.org/1999/xhtml" >
>
Yes. If you do this:
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml" >
<xsl:call-template name="t2"/>
</html>
</xsl:template>
<xsl:template name="t2">
<body/>
</xsl:template>
then you are generating an element whose name is
{http://www.w3.org/1999/xhtml}html, with a child whose name is {}body.
(Using "{uri}local" to indicate an expanded name.) To represent a body
element that's in no namespace as a child of an html element in the
http://www.w3.org/1999/xhtml namespace, the system has to add a namespace
undeclaration xmlns="". Whereas if you generate both elements in the same
namespace, the child element won't need any extra namespace declarations.
Remember that you choose what namespace to put your elements in; the system
then reflects this choice by generating suitable namespace declarations. If
the element is generated as a literal result element, then its name in the
result tree (uri + local-part) is the same as the name of the literal result
element in the stylesheet.
The mistake is to imagine that a namespace declaration in the stylesheet
such as xmlns="http://www.w3.org/1999/xhtml" is copied to become a namespace
declaration in the result tree. That's not the way it works.
Michael Kay
http://www.saxonica.com/
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