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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: matching on several elements, but determine which
You could do something like:
<xsl:template match="h1|h2|h3|h4|h5|h6">
<xsl:element name={concat('title',substring(name(),2,1))}">
<xsl:text>HTML Heading</xsl:text>
</xsl:element>
</xsl:template>
On 10/20/2005, "Dominik Zayer" <dzayer@xxxxxxxxxxxxxx> wrote:
>Hi
>
>I have some very similar XML elements (html headings) which produce very
>similar XSLT output. Know i'm wondering if i could use some wildcards to
>tauten my code.
>
>Here's a part of the XSLT to get you an idea what i am talking about:
><xsl:template match="h1">
> <title1>HTML Heading</title1>
></xsl:template>
><xsl:template match="h2">
> <title2>HTML Heading</title2>
></xsl:template>
>....and so on till <h6>...
>
>Is it possible to do something like:
><xsl:template match="h1|h2|h3|h4|h5|h6">
> #determine which element was matched and write the according output
>element#
></xsl:template>
>
>the matching seems to work this way, but i don't have a clue how to
>output the correct tag...
>
>Thanks for help, hints or a kick in the ass (if this question is really
>stupid) ;)
>
>Best,
>Dominik
>
>
>
>--
>Dominik Zayer > Development
>iconmobile GmbH > Methfesselstr. 32-36 > D-10965 Berlin
>phone +49 30 789 519 13 > fax +49 30 890 686 50
>dzayer@xxxxxxxxxxxxxx > http://www.iconmobile.com
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