RE: (How) can I randomly access the result of a <xsl
First, you put the result in a variable: <xsl:variable name="x"> <xsl:for-each select=... <something/> </xsl:for-each> </xsl:variable> In XSLT 1.0, to address into this variable, you need the xx:node-set() extension (in your case, xalan:nodeset()). In 2.0, you can use it directly. <xsl:variable name="evens" as="xs:integer*"> <xsl:for-each select="1 to 100"> <xsl:sequence select=". * 2"/> </xsl:for-each> </xsl:variable> <xsl:value-of select="$evens"/> Though for this example it's easier to use an XPath "for" expression. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Ferdinand Soethe [mailto:xsl-list@xxxxxxxxxx] > Sent: 14 October 2005 18:18 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: (How) can I randomly access the result of a > <xsl:for-each select="...? > > Perhaps I have searched for the wrong key words ... > > Is it possible to randomly access each member of the set of nodes > created by <xsl:for-each select="... I know I can find the position of > the currently processed node with position() and use the first() and > last() to access the respective nodes. But can I also access each > individual member with something like xyz[memberNo]? > > I figure that there should be a 'root' element that contains the set > but I haven't found a way to address that. > > Btw: I'm using xalan-J > > Thanks a lot. > > -- > Ferdinand Soethe
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