[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: grouping list items by attribute

Subject: Re: grouping list items by attribute
From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx>
Date: Tue, 4 Oct 2005 10:04:07 +0530
li sublist
Please try this stylesheet

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:output method="xml" indent="yes" />

<xsl:template match="/tx.list">
     <xsl:for-each select="tx.li">
         <xsl:when test="@level = '0'">
           <li><xsl:value-of select="tx.p" /></li>
           <xsl:if test="(position() = 1) or
preceding-sibling::tx.li[1]/@level = '0'">
               <li><xsl:value-of select="tx.p" /></li>
               <xsl:call-template name="printli">
                 <xsl:with-param name="list"
select="following-sibling::tx.li" />

<xsl:template name="printli">
   <xsl:param name="list" />

   <xsl:if test="$list/@level = '1'">
     <li><xsl:value-of select="tx.p" /></li>
     <xsl:call-template name="printli">
       <xsl:with-param name="list" select="$list[position() &gt; 1]" />



On 10/4/05, Lynn Alford <lynn.alford@xxxxxxxxxx> wrote:
> Given this as the input
> <tx.list style="ID1c6">
>           <tx.li level="0" number="1.   ">
>             <tx.p style="ID1a2">List1</tx.p>
>           </tx.li>
>           <tx.li level="0" number="2.   ">
>             <tx.p style="ID1a2">List2</tx.p>
>           </tx.li>
>           <tx.li level="1" number="o?=    ">
>             <tx.p style="ID1a2">Sublist 1</tx.p>
>           </tx.li>
>           <tx.li level="1" number="o?=    ">
>             <tx.p style="ID1a2">Sublist 2</tx.p>
>           </tx.li>
>           <tx.li level="1" number="o?=    ">
>             <tx.p style="ID1a2">Sublist 3</tx.p>
>           </tx.li>
>           <tx.li level="0" number="3.   ">
>             <tx.p style="ID1a2">List3</tx.p>
>           </tx.li>
>         </tx.list>
> The preferred outcome would be
> <ol>
>           <li>List1</li>
>           <li>List2</li>
>           <ul>
>                   <li>Sublist 1</li>
>             <li>Sublist 2</li>
>             <li>Sublist 3</li>
>           </ul>
>           <li>List3</li>
>         </ol>
> My basic problem is I can't quite figure out how you can use an increase in
> level to trigger the start of a new list.  Especially when the lists may be
> nested much deeper and any level may be either ordered or unordered
> lists.  Siblings at the same level I can do easily enough.
> Lynn
> Lynn Alford                             Tel     (07) 47 81 6256
> ITR                                             Email:  imla@xxxxxxxxxx
> JCU QLD 4811 Australia                  ICQ: 64096907
> MSN: nicarra60@xxxxxxxxxxx              Y!: nicarra60
> 'I think an "uncatched exception" deserves three bug reports: one for the
> exception, one for not catching it, and one for abuse of the English
> language.'  Michael Kay

Current Thread


Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
First Name
Last Name
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.