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Re: Wildcard problem

Subject: Re: Wildcard problem
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 6 Oct 2005 10:37:53 +0100
Re:  Wildcard problem
> However the translate() funcation eliminates this differences.
> Is that possible or too complicated for XSLT? 

You just need to do the de-duplication before the translate.
eg using keys (muenchian grouping)

<xsl:key name="WAAUX" match="*[starts-with(name(),'WAAUX')]" use="name()"/>


<xsl:value-of select="count(*
[generate-id()=generate-id(key('WAAUX',name())[1])]
[starts-with(translate(name(),'123456789','000000000'),'WAAUX00')])"/>

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