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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: logical AND does not work in xsl:for-each element
I guess you require this
<xsl:for-each select="/GEDCOM/EventRec/Participant[Link/@Ref='X1' and
Role = 'Y1']">
<xsl:value-of select="../Date"/>
</xsl:for-each>
Regards,
Mukul
On 9/25/05, Peter Teichert <peter.teichert@xxxxxx> wrote:
>
> Hi xslt folks,
>
> I know that the logical AND was surely discussed but it could not help me to
solve the problem.
>
> Shortly I have teh following xml structure
>
> <GEDCOM>
> <EventRec>
> <Participant>
> <Link Ref="X1"/>
> <Role>Y1</Role>
> </Participant>
> <Participant>
> <Link Ref="X2"/>
> <Role>Y2</Role>
> </Participant>
> <Participant>
> <Link Ref="X3"/>
> <Role>Y3</Role>
> </Participant>
> <Date>Date1</Date>
> <Place>Place1</Place>
> <Information>Info1</Information>
> </EventRec>
>
> I want to locate a specific participant and extract the nodes Date, Place
and Info with the following xsl:for-each
>
> <xsl:for-each select="/GEDCOM/EventRec/Participant[@Ref='X1' and
Role['Y1']]">
> <xsl:value-of select="../Date"/>
> </xsl:for-each>
>
> The output for both cases separated is correct but when combined it displays
always 3 dates and not only one date
>
> What I am doing wrong here ?
> --
> PTE
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