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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Find elements whose ancestors are the same
 Thanks again to everyone who has replied to these messages. I had no idea how hard this would be. It seemed so simple when I explained it to the client ;-) I'm looking for an XPath expression that will find all elements whose ancestors are the same. By "same" I mean their @name is the same at each level of ancestry (and they appear in the same order). For example, this expression would return a count of 2 for the following XML when filtered on the "daughter" folder (or "mother" or "grandfather" for that matter). <root>
<folder name="grandfather">
<folder name="mother">
<folder name="daughter" />
</folder>
</folder>
<folder name="grandfather">
<folder name="mother">
<folder name="daughter" />
</folder>
</folder>
<folder name="grandmother">
<folder name="father">
<folder name="son" />
</folder>
</folder>
</root>I know it's going to be something like this, but I just can't get my head around it! <xsl:copy-of select="/root//folder[@name = following-sibling::*/@name and ancestor-or-self::*/@name = following-sibling::*/@name/ancestor-or-self::*/@name" /> Thanks in advance! Ted 
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