Re: Key problem. Ordering XML with conditions than ge

About: "RE: Another <xsl:key> problem "

My intentions are educational. :-) I'm a beginner.

Now my problem is to order nodes in groups based on certain characteristics
of their children. (Using DIV tags.) And perhaps seeing to other way I can
find my own solution.

Really I do not have opinion. I used your template and did not obtain
results, because of it I sent the xml again.

Your recursion solution is elegant, but I can't understand the siblings use.

May be you can help me...

____________________________________________________________
My own problem is:

This is language's teacher board offer example. I need sort teacher's offers
by price. And sort teachers from cheapest to most expensive.

With this rule: "If the course can pay with credit card or is not informed,
it's a promotion."

The promotions are a new group. And carry out the teacher's rules.

Other additional complication: courses have two or more teachers. And the
sorted group uses the first teacher's name.

<!-- promotions -->
<xsl:apply-templates select="//grade[(var/pay = 'Credit') or (var/pay = '')]" />
<!-- others -->
<xsl:apply-templates select="//grade[(var/pay != 'Credit') and (var/pay != '')]">
  <xsl:sort select="var/price" data-type="number" />
</xsl:apply-templates>

<xsl:key name="courses-by-teacher" match="course" use="teacher" />
<xsl:key name="teachers" match="teacher" use="." />

<xsl:for-each select="//teacher">
  <!-- alphabetize them -->
  <xsl:sort />

  <!-- teacher occur multiple times, take first occurrence -->
  <xsl:if test="generate-id(.) = generate-id(key('teachers', .)[1])">
    <group>
      <xsl:copy-of select="." />
      <xsl:copy-of select="key('courses-by-teacher', .)" />
    </group>
  </xsl:if>
</xsl:for-each>

--------------------------------------------------
My XSL is:
--------------------------------------------------
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:key name="order1" match="grade" use="((substring(var/pay,1,1))='') or
((substring(var/pay,1,1))='C')" />
<xsl:key name="order2" match="grade"
use="concat(((substring(var/pay,1,1))='') or
((substring(var/pay,1,1))='C'),course[1]/teacher)" />

<xsl:template match='root'> <table>
<!--Expecial logic for C pay nodes.-->

    <xsl:for-each select="grade[count(. | key('order1', 'true')[1]) = 1]">
      <xsl:if test="generate-id()=generate-id(key('order1', 'true'))">

      <tr><td><div><xsl:attribute
name="id">credit_offer</xsl:attribute><table>
      <tr><td>Credit Offer</td></tr>
      <xsl:for-each select="key('order1', 'true')">
            <xsl:sort select="var/price" order="ascending"
data-type="number"/>
                  <xsl:call-template name="course"/>
        </xsl:for-each>
      </table></div></td></tr>
        </xsl:if>
    </xsl:for-each>
  <!--Logic to group nodes with standar pays-->

    <xsl:for-each select="grade[count(. | key('order2',
concat('false',course[1]/teacher))[1]) = 1]">
    <xsl:if test="generate-id()=generate-id(key('order2',
concat('false',course[1]/teacher)))">

      <tr><td><div><xsl:attribute name="id"><xsl:value-of
select="course[1]/teacher"/></xsl:attribute><table>
      <tr><td>Teacher's Leader: <xsl:value-of
select="course[1]/teacher"/></td></tr>
      <xsl:for-each select="key('order2',
concat('false',course[1]/teacher))">

<xsl:sort select="var/price" order="ascending" data-type="number"/>
<xsl:call-template name="course"/>
</xsl:for-each>
</table></div></td></tr>
</xsl:if>
</xsl:for-each>
</table>
</xsl:template>
<!--The rest.-->
<xsl:template name="course"> <tr>
<td><xsl:value-of select="position()"/>.</td>
<td>Price: <xsl:value-of select="var/price"/>.</td>
<td><xsl:apply-templates select='course'/></td>
</tr>
</xsl:template>
<xsl:template match="course">
<br/>teacher: <xsl:value-of select="teacher"/>&#xa0;&#xa0;
class: <xsl:value-of select="class"/>&#xa0;&#xa0;
shift: <xsl:value-of select="shift"/>&#xa0;&#xa0;
Pay: <xsl:value-of select="../var/pay"/>
</xsl:template>
</xsl:stylesheet>

HTH,
Geert