RE: % in xslt printing as ?
I don't have the msxsl documentation to hand but I would guess that if your parameter is named Date then you specify Date="2005-01-01". Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: stuart arnold [mailto:stuart.arnold@xxxxxxxxxxx] > Sent: 22 September 2005 23:59 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: % in xslt printing as ? > > I treied that, I guess I'm missing something. > > I'm calling at: > msxsl.exe testme.xml myfix.xsl param="2005-01-01" -o out.html > > In the XSL, what should I have, I mean, how does it know that > that param > goes with what, eg > <xsl:param name="Date" /> > > Should I have more on the command line or the XSL? > > Thanks for the reply and any help. > > -----Original Message----- > From: Michael Kay [mailto:mike@xxxxxxxxxxxx] > Sent: Thursday, September 22, 2005 6:38 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: % in xslt printing as ? > > > > > > I'm trying to pass a variable to my xsl processor as well, > but I don't > > > know how to recive it in the XSL. What xsl command do I use? > > Use <xsl:param name="nnnn"/> as a top-level element (a child of > xsl:stylesheet). Then refer to the parameter just like a variable, as > $nnnn. The way you actually supply the parameter a value > depends on the > processor API you are using. > > Michael Kay > http://www.saxonica.com/
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