Re: Sorting problem

From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Sorting problem
Date: Wed, 31 Aug 2005 12:49:18 +0100

me> No. keys are what you _do_ use in xslt 1 in this case. (in xslt2 you
me> could use xsl:for-each-group)

Or rather you could use keys here, but in this case, i think you just want
to sort don't you?

 <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0" >
 <xsl:output method="xml" indent="yes"/>

<xsl:template match="root">

<root>
<xsl:for-each select="item">
<xsl:sort data-type="number" select="count(preceding-sibling::item[@type=current()/@type])"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</root>
</xsl:template>


</xsl:stylesheet>


produces

$ saxon item.xml item.xsl
<?xml version="1.0" encoding="utf-8"?>
<root>
   <item type="A" subType="1"/>
   <item type="B" subType="2"/>
   <item type="D" subType="1"/>
   <item type="E" subType="2"/>
   <item type="A" subType="2"/>
   <item type="B" subType="3"/>
   <item type="D" subType="2"/>
   <item type="E" subType="4"/>
   <item type="A" subType="4"/>
   <item type="D" subType="3"/>
   <item type="D" subType="4"/>
</root>

which appears to be what you wanted.

David

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