Re: Exsl str:replace template problems

Kenneth Stephen wrote:

>Hi,
>
>    I'm attempting to work with the EXSL extension template for string
>replacement provided at
>http://www.exslt.org/str/functions/replace/str.replace.template.xsl .
>Here is my code :
>
>	<xsl:template match="text()" priority="2">
>		<xsl:text /><xsl:value-of select="concat('Original = ',.,':::')"
>/><xsl:text />
>		<xsl:call-template name="exsl-str:replace">
>			<xsl:with-param name="string" select="." />
>			<xsl:with-param name="search" select="'&EOL;'" />
>			<xsl:with-param name="replace" select="'&EOL;&TAB;'" />
>		</xsl:call-template>
>	</xsl:template>
>
>...where the entities are defined as 
>
><!DOCTYPE xsl:stylesheet [
>	<!ENTITY EOL "&#x0A;">
>	<!ENTITY TAB "&#x09;">
>]>
>
>    From my debugging, it appears that any instance of &#x0A; is being
>converted to a &#x20 within the replace template. I suspect, the
>following copy-of from that code is the guillty party...
>
>				<!-- this converts the search and replace arguments to node sets
>					if they are one of the other XPath types -->
>				<xsl:variable name="search-nodes-rtf">
>					<xsl:copy-of select="$search" />
>				</xsl:variable>
>
>....but I dont understand the reasons why and how to work around this
>problem. Any ideas?
>  
>

to be precise, what XSLT processor are you using.

Jim Fuller