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RE: Grouping problem

Subject: RE: Grouping problem
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Mon, 1 Aug 2005 22:27:52 +0100
grouping problem
These seem to be solutions to a different problem. The original XML has no
@name attributes.

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: Andrew Franz [mailto:afranz0@xxxxxxxxxxxxxxxx] 
> Sent: 01 August 2005 22:11
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  Grouping problem
> 
> Mukul Gandhi wrote:
> 
> >Thanks Mike for the XSLT 2.0 way to solve the problem. But it was
> >surprising for me that the problem cannot be solved in XSLT 1.0 using
> >preceding-sibling axis.
> >
> >Regards,
> >Mukul
> >  
> >
> 
> Solution #1:
> <xsl:template match="groups">
>     <xsl:for-each select="group">
>     <xsl:sort select="@name" />
>     <xsl:if test="not(@name = preceding-sibling::group/@name)">
>         <group name="{@name}" />
>     </xsl:if>
>     </xsl:for-each>
> </xsl:template>
> 
> Solution #2:
> <xsl:template match="groups">
>     <xsl:for-each select="group">
>     <xsl:sort select="@name" />
>         <xsl:apply-templates select="." />
>     </xsl:for-each>
> </xsl:template>
> 
> <xsl:template match="group[(@name = preceding-sibling::group/@name)]" 
> priority="+1" />
> <xsl:template match="group">
>         <group name="{@name}" />
> </xsl:template>
> 
> Solution #3:
> <xsl:key name="k2" match="group" use="@name" />
> 
> <xsl:template match="groups">
>     <xsl:for-each select="group">
>     <xsl:sort select="@name" />
>         <xsl:apply-templates select="." />
>     </xsl:for-each>
> </xsl:template>
> 
> <xsl:template match="group" priority="-1" />
> <xsl:template match="group[generate-id() = generate-id(key('k2', 
> @name)[1])]">
>     group[<xsl:value-of select="@id" />]=<xsl:value-of select="@name" 
> /><br/>
> </xsl:template>
> 
> 
> 
> >On 8/1/05, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> >  
> >
> >>When comparing two node-sets,
> >>
> >>  X = Y
> >>
> >>means "some $x in X equals some $y in Y"
> >>
> >>But when you do
> >>
> >>  name(X) = name(Y)
> >>
> >>you are comparing two strings, not two node-sets. If X is a 
> node-set, then
> >>name(X) is the name of the first node in X, and name(Y) is 
> the name of the
> >>first node in Y. (In XSLT 2.0, with version="2.0", you 
> would get an error
> >>trying to apply name() to a node-set containing more than 
> one node. The
> >>change has been made to catch this common mistake.)
> >>
> >>In 2.0 you can write
> >>
> >>select="*[not(name() = preceding-sibling::*/name())]"
> >>
> >>but of course it would be more efficient to use xsl:for-each-group.
> >>
> >>Michael Kay
> >>http://www.saxonica.com/
> >>
> >>
> >>    
> >>
> >>>-----Original Message-----
> >>>From: Mukul Gandhi [mailto:gandhi.mukul@xxxxxxxxx]
> >>>Sent: 01 August 2005 07:57
> >>>To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >>>Subject:  Grouping problem
> >>>
> >>>I have the following XML file -
> >>><?xml version="1.0" encoding="UTF-8"?>
> >>><root>
> >>>   <a>1</a>
> >>>   <b>2</b>
> >>>   <d>3</d>
> >>>   <d>4</d>
> >>>   <b>5</b>
> >>>   <b>6</b>
> >>>   <c>7</c>
> >>>   <c>8</c>
> >>>   <a>9</a>
> >>></root>
> >>>
> >>>I am trying to do grouping operation with the following XSL -
> >>><?xml version="1.0" encoding="UTF-8"?>
> >>><xsl:stylesheet version="1.0"
> >>>xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> >>>
> >>>      <xsl:output method="xml" version="1.0" encoding="UTF-8"
> >>>indent="yes"/>
> >>>
> >>>      <xsl:template match="/root">
> >>>         <groups>
> >>>           <xsl:for-each select="*[not(name() =
> >>>name(preceding-sibling::*))]">
> >>>            <group name="{name()}" />
> >>>           </xsl:for-each>
> >>>         </groups>
> >>>      </xsl:template>
> >>>
> >>></xsl:stylesheet>
> >>>
> >>>I am expecting output -
> >>><groups>
> >>>   <group name="a" />
> >>>   <group name="b" />
> >>>   <group name="c" />
> >>>   <group name="d" />
> >>></groups>
> >>>
> >>>But I get output -
> >>><?xml version="1.0" encoding="UTF-8"?>
> >>><groups>
> >>><group name="a"/>
> >>><group name="b"/>
> >>><group name="d"/>
> >>><group name="d"/>
> >>><group name="b"/>
> >>><group name="b"/>
> >>><group name="c"/>
> >>><group name="c"/>
> >>></groups>
> >>>
> >>>Where is the problem?
> >>>
> >>>This is tested with Xalan-J 2.6.0 and Saxon 8.4
> >>>
> >>>Regards,
> >>>Mukul

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