|
[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
[Recent Entries]
[Reply To This Message]
Re: AW: xsl:key function help
Subject: Re: AW: xsl:key function help
From: "Joris Gillis" <roac@xxxxxxxxxx>
Date: Thu, 04 Aug 2005 09:40:01 +0200
|
Tempore 08:22:25, die 08/04/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit David Preuss <d.preuss@xxxxxxxxxxx>:
That is OK so far because I can understand. Regarding the Muenchian method
which is described on Jenis site I tried the following:
<?xml version='1.0' encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="Categories" match="Tip" use="@Topic" />
<xsl:output method="xml"/>
<xsl:template match="/">
<xsl:apply-templates select="Tip[generate-id(.) =
generate-id(key('Categories',@Topic)[1])]"/>
</xsl:template>
<xsl:template match="Tip" >
<xsl:for-each select="key('Categories', @Topic)">
<xsl:value-of select="@Subtopic"/>
</xsl:for-each>
</xsl:template>
The usage of the 'key()' function and the implementation of the Muenchian grouping is 100% correct.
The problem is really much easier:
You do not want <xsl:template match="/">
but instead: <xsl:template match="TipDatabase">
regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
B+N N1N;N.N8N5N9N1 N:N1N9 ON? N;N,N4N9 ON,N=ON1 N2N3N1N/N=N?ON= N1OO ON,N=O B;

|
PURCHASE STYLUS STUDIO ONLINE TODAY!
Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!
Download The World's Best XML IDE!
Accelerate XML development with our award-winning XML IDE - Download a free trial today!
Subscribe in XML format
| RSS 2.0 |
|
| Atom 0.3 |
|
|