Re: Printing ancestor elements of all element nodes

Thank you David! This is marvellous..  My attempt was -

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output method="text" />

    <xsl:template match="/">
       <xsl:for-each select="//*">
          Element name <xsl:value-of select="name()"
/><xsl:text>&#xa;</xsl:text>
          Ancestor elements of this element
          <xsl:text>&#xa;</xsl:text>
          <xsl:text>&#xa;</xsl:text>
          <xsl:call-template name="printAncestors">
              <xsl:with-param name="node" select="." />
          </xsl:call-template>
       </xsl:for-each>
    </xsl:template>

    <xsl:template name="printAncestors">
       <xsl:param name="node" />

       <xsl:choose>
			<xsl:when test="$node/parent::*">
                <xsl:value-of select="name($node)" />,
                <xsl:call-template name="printAncestors">
                   <xsl:with-param name="node"
select="$node/ancestor::*"/>
                </xsl:call-template>
			</xsl:when>
			<xsl:otherwise>
               <xsl:value-of select="name($node)" />,
			</xsl:otherwise>
	   </xsl:choose>
    </xsl:template>

</xsl:stylesheet>

But this did'nt work.. ;)

THANK YOU.

Regards,
Mukul

On 8/3/05, David Carlisle <davidc@xxxxxxxxx> wrote:
>
> <xsl:for-each select="//*">
>  <xsl:text>&#10;</xsl:text>
>  <xsl:value-of select="name()"/>
>  <xsl:text> - </xsl:text>
>  <xsl:for-each select="ancestor::*">
>  <xsl:sort select="-count(ancestor::*)"/>
>  <xsl:value-of select="name()"/>
>  <xsl:if tets="position()!=last()">,</xsl:if>
>  </xsl:for-each>
>  </xsl:for-each>
>
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