|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XSL Unique values
Hi,
Tempore 22:40:37, die 08/31/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Prakash R <raghits@xxxxxxxxx>: Is there any way using XSL I can get the unique metadata[@fieldid=3]/fieldvalues for each product. I know I can do it across the entire XML doc. In this example for product(name=shirt) it would be RG,LN and SM , product(name=t-shirt) it would be AA,BB,CC,DD,EE. I want to be able to get these separately for each product and iterate through it within the product if possible. Close examination of a working sample (such as below) is always the best method to learn in my opinion... <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:key name="metadata" match="metadata" use="concat(generate-id(ancestor::product),@fieldid,fieldvalue)"/> <xsl:template match="product"> <xsl:value-of select="name"/>: <xsl:for-each select=".//metadata[generate-id(
key('metadata',concat(generate-id(current()),3,.))[1])=generate-id()]">
<xsl:value-of select="fieldvalue"/>-
</xsl:for-each>
</xsl:template></xsl:stylesheet> regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) B+Numquam mores quos extuli referoB; - Seneca , Ad Lucilium I, 7
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|

Cart








