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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Joining sibling elements
Hi Mukul,
this is a good idea and I'll try to use variables for comparing. Note that I have to retain all attributes and elements which is quite tricky in scenarios like: <a><b atr1="12"><c><d>text</d></c></b><b atr1="12><c><d> </d></c><b><b atr1="13"><c><d>etc.</d></c><b> especially when I cannot predict which and how many elements would appear under <b> but I know that <d> contains only text value. Seems to me I have to compare rtfs containing all elements except for <d>. So I would try to create two variables: first one containing such rtf of the current <b>, and a second one containing following-sibling of this current <b>. If they are the same, copy text() from <d> to the rtf of current <b>, and write this rtf to the output. If not, write both rtfs to the output. The problem is that I don't know how to construct the for-each statement to process exactly the current <b> and its following sibling, and to skip the following sibling from processing... Best regards, Marcin Mukul Gandhi wrote: Given this XML - <?xml version="1.0" encoding="UTF-8"?> <root> <a><b>this</b><b>this 1</b><b>this 2</b></a> <a><b>this 3</b></a> <a><b>this 4</b><b>this 5</b></a> <a><b>this 6</b><b>this 7</b><b>this 8</b><b>this 9</b></a> <a><b>this 10</b><b>this 11</b><b>this 12</b><b>this 13</b></a> </root> This XSLT stylesheet - <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:common="http://exslt.org/common" exclude-result-prefixes="common">
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