RE: Sorting Problem

With Saxon 8.4 I get

   <tr>
      <td>Jason</td>
      <td>filterBean</td>
      <td>1</td>
   </tr>
   <tr>
      <td>Matt</td>
      <td>retrieveUserPreferencesBean</td>
      <td>1</td>
   </tr>
   <tr>
      <td>Joe</td>
      <td>retrieveUserPreferencesBean</td>
      <td>2</td>
   </tr>

What product/version are you using?

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Dhami, Ankit (UMR Student) [mailto:atdhfb@xxxxxxx] 
> Sent: 07 July 2005 15:13
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Sorting Problem
> 
> Hi guys,
> 
> Here is the XML file:
> 
> <all>
> <log_entry run_time="4084" 
> action="retrieveUserPreferencesBean" username="Matt"/>
> <log_entry run_time="4085" action="filterBean" username="Jason"/>
> <log_entry run_time="4086" 
> action="retrieveUserPreferencesBean" username="Joe"/>
> <log_entry run_time="4087" 
> action="retrieveUserPreferencesBean" username="Joe"/>
> </all>
> 
> 
> Here is the sorting part of XSL file:
> 
> <xsl:for-each-group select="//log_entry" group-by="@action">
> <xsl:sort select="count(current-group()/@action)" order="ascending"/>
> <xsl:for-each-group select="current-group()" group-by="@username">
> <tr>
> <td><xsl:value-of select="./@username"/></td>
> <td><xsl:value-of select="./@action"/></td>
> <td><xsl:value-of select="count(current-group()/@action)"/></td>
> </tr>
> </xsl:for-each-group> 
> </xsl:for-each-group> 
> 
> 
> The output HTML is:
> 
> <tr>
> <td>Matt</td>
> <td>retrieveUserPreferencesBean</td>
> <td>1</td> ..........( count field)
> </tr>
> <tr>
> <td>Joe</td>
> <td>retrieveUserPreferencesBean</td>
> <td>2</td>..........( count field)
> </tr>
> <tr>
> <td>Jason</td>
> <td>filterBean</td>
> <td>1</td>..........( count field)
> </tr>
> 
> which is not as expected since it did not sort it based on count.
> 
> 
> Here, I am trying to sort the "count" column based on value 
> obtained by function count().
> 
> Any replies appreciated.
> 
> Thanks,