Re: Sum of identical nodes

Each file in File1 and File2 have few hundreds nodes of <moid></moid>
and <mt></mt>. My biggest hindrance is how to recursively sum up each
node from each nodeset.

<xsl:param name="file1" select="/"/>
<xsl:param name="file2" select="document('file2.xml')"/>

<xsl:template match="/">
<xml>
	<xsl:apply-templates select="$file1/xml/*" mode="merge"/>
</xml>
</xsl:template>

<xsl:template match="mt" mode="merge">
	<xsl:variable name="pos" select="position()"/>
	<xsl:copy>
		<xsl:value-of select="sum(. | $file2/xml/*[$pos])"/>
	</xsl:copy>
</xsl:template>

<xsl:template match="moid" mode="merge">
	<xsl:copy-of select="."/>
</xsl:template>

regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
"N N1N;N.N8N5N9N1 N:N1N9 ON? N;N,N4N9 ON,N=ON1 N2N3N1N/N=N?ON= N1OO ON,N=O	"