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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Can a named template return a node list?
Sorry in advance for my terminology. Is it possible for a named
template to return a node list? Here is some simplified XML with which
I have been experimenting:
<root>
<node1 attr="node1attrval">
<node1a>node1atext</node1a>
</node1>
<node2 attr="node2attrval">
<node2a>node2atext</node2a>
</node2>
</root>And the XSL I have been trying: <xsl:template match="*">
<xsl:variable name="somenode">
<xsl:call-template name="sometemplate" />
</xsl:variable>
<xsl:value-of select="$somenode/@attr" />
</xsl:template><xsl:template name="sometemplate"> <xsl:copy-of select="/root/node1" /> </xsl:template> The reference to $somenode/@attr gives an error. I think the problem is with copy-of - I want it to return a reference to a node, but it seems to return the value of the node. Is there some other function or approach I should try? I have tried value-of and copy, and I am hoping to stay away from XSL extensions if possible. I cannot use XSL 2. Thanks, -John
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