Re: Using xsl:for-each for every 2 elements ?

Hi Ahsan,
   Making a strange guess to the difficulty you are
facing, here is the XSLT I think that should solve the
problem .. 

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  
<xsl:output method="xml" indent="yes" />
  
<xsl:template match="/">
  <groups>
    <xsl:for-each select="//*[(position() mod 2) =
0]">
        <group>
          <xsl:copy-of select="(preceding::*[1] |
ancestor::*[1]) | (preceding::*[2] | ancestor::*[2])"
/>
        </group>
    </xsl:for-each>
  </groups>  
</xsl:template>
  
</xsl:stylesheet>

Regards,
Mukul

--- Ahsan Ali <doubleletter@xxxxxxxxx> wrote:
> Thanks Mukul.
> 
> In this case, how do I refer to the _two_ elements
> selected.. Using
> '.', I can display only the second element...
> 
> Regards,
> 
> Ahsan
> 
> On 5/31/05, Mukul Gandhi <mukul_gandhi@xxxxxxxxx>
> wrote:
> > Hi Ahsan,
> >    Please try this XSL, for processing every two
> > elements ..
> > 
> >    <xsl:for-each select="//*[(position() mod 2) =
> 0]">
> >      <!-- Processing you wish -->
> >    </xsl:for-each>
> > 
> > Regards,
> > Mukul
> > 
> > --- Ahsan Ali <doubleletter@xxxxxxxxx> wrote:
> > > Hi,
> > >
> > > Is it possible to use xsl:for-each for every two
> > > elements ?
> > >
> > > E.g
> > > ----------
> > > <data>
> > >   <flights>
> > >    <flt>onward</flt>
> > >    <flt>return</flt>
> > >    <flt>onward</flt>
> > >    <flt>return</flt>
> > >   </flights>
> > >
> > >  <availability>
> > >   <avail>N</avail>
> > >   <avail>Y</avail>
> > >   <avail>N</avail>
> > >   <avail>Y</avail>
> > >   </availability>
> > >
> > > </data>
> > > --------
> > > The second part of the problem is that, the
> above
> > > have to be
> > > iterated/grouped using a method that would still
> > > allow me to somehow
> > > co-relate the first <avail> in <availability>
> with
> > > the first <flt> in
> > > <flights>. That's my second question.. how to
> > > co-relate that since
> > > their in the same level of hierarchy  ??
> > >
> > > Thanks,
> > >
> > > Ahsan
> > >
> > >
> > 
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> 

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