RE: xsl:attributes as parameter to a template

An xsl:with-param element with content defines a document node, the root of
a result tree fragment. It's a recoverable error to create an attribute node
as a child of a document root node; the processor can either report the
error, or ignore the attribute. It seems that your processor has chosen the
latter.

Even if it were possible to create a free-standing attribute node in XSLT
1.0 (it's allowed in 2.0), xsl:value-of would copy the string-value of the
attribute as a new text node; it you wanted to copy the attribute to the new
element, you would need to use xsl:copy-of.

Michael Kay
http://www.saxonica.com/ 


> -----Original Message-----
> From: Jan Tietjens [mailto:jan.tietjens@xxxxxxxxxxxxxx] 
> Sent: 03 May 2005 10:37
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  xsl:attributes as parameter to a template
> 
> Hello,
> I am not understanding why the following xslt snipped 
> produces an empty 
> 'someElement' element (XSLT 1.0):
> 
>     <xsl:template match="/">
>         <xsl:call-template name="printSomeAttributes">
>             <xsl:with-param name="attributes">
>                 <xsl:attribute name="juhu">Hello 
> World!</xsl:attribute>
>             </xsl:with-param>
>         </xsl:call-template>
>     </xsl:template>
>    
>     <xsl:template name="printSomeAttributes">
>         <xsl:param name="attributes"/>
>         <xsl:element name="someElement">
>             <xsl:value-of select="$attributes"/>
>         </xsl:element>
>     </xsl:template>
> 
> Thank you for your answer(s).
> 
> Best regards,
> 
> -- 
> Jan Tietjens
> 
> Gentleware AG
> www.gentleware.com
> 
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