RE: Print all root node attributes

> > <xsl:for-each select="*">
> >   <xsl:value-of select="name()" />
> >       <xsl:for-each select="@*">
> >          <xsl:value-of select="current()" />
> 
> The current() function returns the node matched by the template.
> Try
>   <xsl:value-of select="." />
> instead.
> 
> J.Pietschmann


Not so. As a self-contained XPath expression, current() returns exactly the
same as ".". It's only inside a predicate that the result is different.

Michael Kay
http://www.saxonica.com/