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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] HELP, Validate generated XML file to a new XML schema
 XML document <?xml version="1.0"?> <Unit xmlns="http://www.xml.com/xml/unit" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xml.com/xml/unit unit.xsd"> <Units> <Unit_Code>5555</Unit_Code> <Unit_Name>System</Unit_Name> </Units> </Unit> XSL Stylesheet <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:unit="http://www.monash.edu.au/xml/unitManagement" > <xsl:output method="xml"/> <xsl:template match="/"> <xsl:element name="Unit_Planning" xmlns="http://www.xml.com/xml/unit" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xml.com/xml/unit newUnit.xsd"> <xsl:for-each select="unit:Unit/unit:Units"> <xsl:element name="Unit"> <xsl:element name="Unit_Code"> <xsl:value-of select="unit:Unit_Code"/> </xsl:element> <xsl:element name="Unit_Name"> <xsl:value-of select="unit:Unit_Name"/> </xsl:element> </xsl:element> </xsl:for-each> </xsl:template> </xsl:stylesheet> I wish to display XML that will validate to a new XML schema file. Hope to display XML <?xml version="1.0"?> <Unit xmlns="http://www.xml.com/xml/unit" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xml.com/xml/unit newUnit.xsd"> <Units> <Unit_Code>5555</Unit_Code> <Unit_Name>System</Unit_Name> </Units> </Unit> Can anyone out there pls help me out? I fail to display the exactly what I want. I need to validate to a new schema from what I create. It still be generate the XML file but do not include any of the schemalocation details in the root element. Can anyone show me how to do it in XSL? I wish to know a way to validate to a new schema and show all the details. Thanks 
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