Re: For-each loop or recursion
> > I need to compare current and next values of the node var2 [and var3] > > and find the first occurrence when var2[position()] = var2[next, i.e. > > position()+1] > > Are you saying that is impossible to do in XSLT ? > > It's almost certainly possible to do what you want but your decription > is pretty hard to follow. You need to describe the transformation that > you want to do not just use bits of XPath and hope that we understand > what you want. Xpath's position() function for example does not relate > to the position of a node within a tree (a node can have any number of > values returned buy position(), depending on how the node is > selected). I'm _guessing_ that what you want to know is the sibling order > of the node in the input tree in which case you might want > following-sibling::* but that is just a guess. OK, lets try to get a position of the first occurrence when var2 = max node. As I said, I don't want to change the order of the nodes in a tree with sort. What would be a correct syntax ? <xsl:for-each select=mystruct/myarray1/myvar> <xsl:if var2=*[last()]> <xsl:value-of select="position()"> </xsl:if> </xsl:for-each> The goal is to trim the table [see my previous post], get rid of multiple identical occurrences of rebate1 & rebate2. Do you understand me ? Thank you, Oleg. > > I want from inside for-each loop mystruct/myarray1[i]/myvar > [or does it require recursion?] > compare the values is the parallel branch, > of parallel "current" node ../../myarray2[i]/myvar/var3 and its "next node". > Again, where: > mystruct/myarray1[i]/myvar/var2 and > mystruct/myarray2[i]/myvar/var3 > > Again you are just typing in syntactically correct XPath and asking "can > I do that" since the Xpath you typed above is syntactically correct then > clearly you can do that, but I have no idea if that will do what you > want, as you've not said what you are trying to do. For example do your > elements with name myarray1 have child elements with name i ? If they do > not, then the above XPath's will select nothing. > > > Is there an easy way to find out the max value of the node (child elements) > > without sorting it ? > > The sequence of nodes I am dealing with is supposed to be in increasing order, > > If you know it's already sorted, just take the last > select="*[last()]" > or in your case take the last of each then you only have two itemsto > compare which you can do with > to work out the overall maximum. > > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star. The > service is powered by MessageLabs. For more information on a proactive > anti-virus service working around the clock, around the globe, visit: > http://www.star.net.uk > ________________________________________________________________________
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