RE: XSL distinct group by date

Peter,
My apologies for the late reply. I had another project pop up in between
this one. Thank you for the suggestion. That solved my problem. However,
I've encountered another issue. 

I've been using this as a guide:
http://sources.redhat.com/ml/xsl-list/2000-07/msg00458.html

I've slightly altered that XML set to fit the structure of my XML and it
doesn't do as I would have expected. I'm hoping someone can explain why to
me.

Altered XML:

<company>
	<projects>
		<project>
			<name>Customer 1</name>
		</project>
		<project>
			<name>Customer 2</name>
		</project>
		<project>
			<name>Customer 2</name>
		</project>
	</projects>
	<papers>
		<paper>
			<title>A Paper Title</title>
		</paper>
	</papers>
</company>

Now if I use the XSLT in the above link
(http://sources.redhat.com/ml/xsl-list/2000-07/msg00458.html), it does
return the distinct customer name values, but it also writes out the value
of the nodes outside the /projects level, yielding: Customer 1Customer 2 A
Paper Title

Any explanation of this behavior would be very helpful.

Thank you and again, my apologies for the delay in response.

Mindy

> >-----Original Message-----
> >Date: Mon, 25 Apr 2005 13:23:55 -0400
> >To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> >From: "Jacoby, Peter R." <PJACOBY@xxxxxxxxxxxx>
> >Subject: RE:  XSL distinct group by date
> >Message-ID: 
> ><3CFEFF6C55FB5C42A6E68E9521D5C436DBC219@xxxxxxxxxxxxxxxxxxxx>
> >
> >Mindy,
> >
> >If you want to group your elements by only the year portion 
> >of the date, =
> >then
> >you need to change your xsl:key use attribute to only look 
> >at the year.
> >Something like:
> >
> ><xsl:key name=3D"documents-by-date" match=3D"newsitem" =
> >use=3D"substring(date,
> >string-length(date)-3, 4)" />
> >
> >Then you would call it with the same=20
> >key('document-by-date', '2004')=20
> >
> >or in your code
> >key('documents-by-date', substring(date, string-length(date)-3, 4))
> >
> >One other piece that you may want to try is grouping more than just =
> >newsitem
> >elements together (I couldn't tell from your original post 
> >if this is =
> >what you
> >are looking for or not).  You can use the union operator | 
> >to match on =
> >more than
> >one named element.  Something like:
> ><xsl:key name=3D"documents-by-date" match=3D"newsitem  | 
> >whitepapers |
> >pressreleases" use=3D"substring(date, string-length(date)-3, 4)" />
> >
> >As you said, you could make it (slightly) simpler by storing 
> >the year in =
> >a
> >separate element (or attribute), but it's not necessary to get the =
> >desired
> >functionality.
> >
> >Hope this helps.
> >
> >-Peter