Re: A challenge.. Group Periods of Data (1..5, 2..8,

Hi Karl,
  I approached the problem as follows -

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml" indent="yes" />

<xsl:variable name="start1" select="1" />
<xsl:variable name="end1" select="12" />
<xsl:variable name="start2" select="14" />
<xsl:variable name="end2" select="30" />
  
<xsl:template match="/A">
   <result>
     <period begins="{$start1}" ends="{$end1}">
       <xsl:for-each select="B[(@period_begin &gt;=
$start1) and (@period_end &lt;= $end1)]">
         <xsl:sort select="@period_begin"
data-type="number" />
         <xsl:copy-of select="." />
       </xsl:for-each>
     </period>
     <period begins="{$start2}" ends="{$end2}">
       <xsl:for-each select="B[(@period_begin &gt;=
$start2) and (@period_end &lt;= $end2)]">
         <xsl:sort select="@period_begin"
data-type="number" />
         <xsl:copy-of select="." />
       </xsl:for-each>
     </period>
   </result>
</xsl:template>
  
</xsl:stylesheet>

When the above XSLT stylesheet is given this XML as
input -

<?xml version="1.0" encoding="UTF-8"?>
<A>
  <B period_begin="14" period_end="16"/>
  <B period_begin="2" period_end="7"/>
  <B period_begin="16" period_end="20"/>
  <B period_begin="1" period_end="5"/>
  <B period_begin="4" period_end="12"/>
  <B period_begin="16" period_end="30"/>
  <B period_begin="3" period_end="10"/>
</A>

The output recieved is -

<?xml version="1.0" encoding="utf-8"?>
<result>
   <period begins="1" ends="12">
      <B period_begin="1" period_end="5"/>
      <B period_begin="2" period_end="7"/>
      <B period_begin="3" period_end="10"/>
      <B period_begin="4" period_end="12"/>
   </period>
   <period begins="14" ends="30">
      <B period_begin="14" period_end="16"/>
      <B period_begin="16" period_end="20"/>
      <B period_begin="16" period_end="30"/>
   </period>
</result>

The other answers are brilliant.. But I thought of
giving it a try myself, and seeing how my approach
will differ with other people's answers! 

(I don't know if I should have answered at this stage,
as your question is already answered :) But just
thought of..)

Regards,
Mukul

--- Karl Stubsjoen <kstubs@xxxxxxxxx> wrote:
> A challenge, group the following XML into 2 periods.
>  The periods are
> arbitrary, but for this example they happen to be:
> Period 1:  1 - 12
> Period 2:  14 - 30
> 
> Expected Result:
> <result>
>   <period begins="1" ends="12">
>     <B period_begin="1" period_end="5"/>
>     <B period_begin="2" period_end="7"/>
>     <B period_begin="3" period_end="10"/>
>     <B period_begin="4" period_end="12"/>
>   </period>
>   <period begins="14" ends="30">
>     <B period_begin="14" period_end="16"/>
>     <B period_begin="16" period_end="20"/>
>     <B period_begin="16" period_end="30"/>
>   </period>
> </result>
> 
> Source XML / Result (sorted)
> <A>
>   <B period_begin="1" period_end="5"/>
>   <B period_begin="2" period_end="7"/>
>   <B period_begin="3" period_end="10"/>
>   <B period_begin="4" period_end="12"/>
>   <B period_begin="14" period_end="16"/>
>   <B period_begin="16" period_end="20"/>
>   <B period_begin="16" period_end="30"/>
> </A>
> 
> Source XML / Result (un-sorted)
> <A>
>   <B period_begin="14" period_end="16"/>
>   <B period_begin="2" period_end="7"/>
>   <B period_begin="16" period_end="20"/>
>   <B period_begin="1" period_end="5"/>
>   <B period_begin="4" period_end="12"/>
>   <B period_begin="16" period_end="30"/>
>   <B period_begin="3" period_end="10"/>
> </A>
> 
> 


		
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