Re: substitute variable value into xpath expression -
This is a FAQ. msxsl:node-set($TRAINING_TYPE_XMLDOC)/$XML_PARENT/$XML_CHILD"> $XML_PARENT contains a string as does XML child so your expression is equivalent to msxsl:node-set($TRAINING_TYPE_XMLDOC)/'training_types'/'training_type'"> which is a syntax error. people often seem to expect this to work in XSLT but it is just the same as having x = " + 1" y = 1 in C and hoping that y x expands to 1 + 1 and evaluates to 2. In general you need an extension function that evaluates strings as Xpaths, but here you can do <xsl:for-each select="msxsl:node-set($TRAINING_TYPE_XMLDOC)/*[name()=$XML_PARENT]/*[name()=$XML_CHILD}"> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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