Re: If Current Node Is Ancestor!

Hi,
        Are you particular about using the ancestor axis bcos I don't think
it is of much use here. You can do this using the descendant axis as
follows:

     <xsl:if test="descendant::menu[@dept = $dept]">
          <xsl:value-of select="'node found'"/>
     </xsl:if>


This is assuming I understood your requirement right.

Cheers,
Omprakash.V







                                                                                                                    
                    Brian Chrisman                                                                                  
                    <incubus@shell        To:     xsl-list@xxxxxxxxxxxxxxxxxxxxxx                                   
                    .izap.com>            cc:     (bcc: omprakash.v/Polaris)                                        
                                          Subject:     Re:  If Current Node Is Ancestor!                       
                    04/12/2005                                                                                      
                    09:04 AM                                                                                        
                    Please respond                                                                                  
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On Tue, Apr 12, 2005 at 01:19:41PM +1000, Adam J Knight wrote:
> Hi all,
>
> I am trying to test whether a current node is an ancestor of a menu node
> with a dept attribute equal to $depth. I appear to be struggling with
this
> conceptually and would appreciate any help!!
>
> <xsl:if test="//menu[@dept != $dept]/ancestor::menu ">
>   <xsl:attribute name="class">nav_close</xsl:attribute>
> </xsl:if>

Here's one way I *think* you could do it.. but I haven't
tried it.. and I don't use this functionality much..

<xsl:variable name="my-depth" select="count(ancestor::*)"/>
<xsl:if test=".//menu[(count(ancestor::*) - $my-depth) = $depth]">
  foo
</xsl:if>

>
> Cheers,
> Adam
> ?






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