Re: Select nodes with equal position

This transformation shows how to avoid evaluating the position in an
xsl:variable:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 
 <xsl:output omit-xml-declaration="yes"/>
  
  <xsl:template match="/">
    <xsl:for-each select="/*/*/entry">
      <xsl:value-of select=
         "/*/colspec[position() 
        = 
         count(current()/preceding-sibling::entry)+1]/@colname"/>
      <xsl:text>&#xA;</xsl:text>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

When performed on the original xml source document:

<table>
  <colspec colname="c1"/>
  <colspec colname="c2"/>
  <colspec colname="c3"/>
  <row>
    <entry colname="c1">r1_1</entry>
    <entry colname="c2">r1_2</entry>
    <entry colname="c3">r1_2</entry>
  </row>
</table>

the correct result is produced:

c1
c2
c3


Cheers,
Dimitre Novatchev



On Apr 3, 2005 4:28 AM, Norbert Heidbrink <nh@xxxxxxxx> wrote:
> Hallo everyone,
> 
> depending on the postion() of a certain node I would like to select
> another node with the same position.
> It works if I invent a variable.
> But I wonder if there is a way to do it without the use of a variable?
> 
> XML:
> 
> <table>
>  <colspec colname="c1"/>
>  <colspec colname="c2"/>
>  <colspec colname="c3"/>
>  <row>
>    <entry colname="c1">r1_1</entry>
>    <entry colname="c2">r1_2</entry>
>    <entry colname="c3">r1_2</entry>
>  </row>
> </table>
> 
> XSL:
> <xsl:template match="entry">
>  <xsl:variable name="mypos">
>    <xsl:value-of select="position()"/>
>  </xsl:variable>
>  <xsl:value-of select="../../colspec[position() = $mypos]/@colname"/>
> </xsl:template>
> 
> Best regards and thanks for your comments,
> Norbert Heidbrink