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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: First attempt at xsl:result-document
 > Thanks once again for the reply. I've retested my application and do
> not think the URI is the problem. As an example
>
> .
> .
> .
> <xsl:for-each select="part">
> <xsl:variable name="filename" select="concat('file:///',
> position(), '.htm'"/>
> <xsl:result-document href={$filename}" format="html">
> <html>
> <body>
>
> <!-- Test -->
> <xsl:value-of="/act/title"/>
> <!--End of Test -->
>
> <xsl:apply-templates mode="content"/>
> </body>
> </html>
> </xsl:result-document>
> </xsl:for-each>
> </xsl:template>
>
> Now let's say I have 4 parts in an xml document. I do get 5 files in
> the end (1 table of contents and 4 parts) and each file is named as
> expected and each file picks up the title. However none of the files
> pick up any content from the <xsl:apply-templates mode="content"/>.
>
Your example XML was:
<act>
> > <part>this is a part we will divide a file on</part>
> > <section>This is a section</section>
> > <clause>This is a clause</clause>
> > <part>This is another part, in the new scheme of things, a second
> > file</part>
> > <section>Yet another section</section>
> > </act>
In this example, the only child of the <part> element is a single text node.
I would expect this text to be output as a result of the
<xsl:apply-templates mode="content"/> call. I would not expect the section
and clause elements to be output, because they are not children of the
<part>.
Michael Kay
http://www.saxonica.com/
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