Re: xsl:for-each...iteration question

Hi Paul,
  Please also try this XSL.. You may like it..

<?xml version="1.0"?> 
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
  
<xsl:output method="xml" indent="yes" />
  
<xsl:variable name="exclude"
select="document('exclude.xml')" />
  
<xsl:template match="node() | @*">
  <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
  </xsl:copy>
</xsl:template>
  
<xsl:template match="*[@attr-name =
$exclude/exclude-list/exclude-attr]" />
  
</xsl:stylesheet>

This is a modified identity stylesheet.. The 2nd
template excludes those elements, whose attr-name
attribute has value matching that in exclude file..

I have found.. identity template is a really powerful
piece of code which lets us do complex things..

Regards,
Mukul

--- Paul Coletti <pcoletti@xxxxxxxxxx> wrote:
> This has been answered before I'm sure but doing a
> relevant search in the archives is tricky.
>  
> I've an input doc containing a number of modify-attr
> elements
> <modify>
>   <modify-attr attr-name = "abc"/> 
>   <modify-attr attr-name = "123"/>
>   <modify-attr attr-name = "789"/>
> </modify>
>  
> I have another document containing a list of
> prohibited attributes.
> <exclude-list>
>   <exclude-attr>123</exclude-attr>
> </exclude-list>
>  
>  
> I want to iterate over my input doc and copy all
> those modify-attr elements that are NOT in the
> exclude list to the output.
>  
> <xsl:template match="modify/modify-attr">
>   <xsl:variable name="currentAttr"
> select="@attr-name"/>
>   <xsl:variable name="currentNode" select="."/>
>  
>   <xsl:for-each
>
select="document('excludedoc')/exclude-list/exclude-attr">
>     <xsl:when test="$currentAttr=.">
>       <xsl:message>Exclude</xsl:message>
>     </xsl:when>
>     <xsl:otherwise>
>       <xsl:copy-of select="$currentNode"/>
>     </xsl:otherwise>
>   </xsl:for-each>
>  
> </xsl:template>
>  
> Obvisouly, this is flawed, I get multiple
> modify-attr elements copied to the output because I
> cannot see a way of ensuring the for-each only
> copies a permitted node once and once only.
>  
> I've a feeling this is approaching the problem from
> the wrong way....
> 
> 


		
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