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in this xsl , why dont get result with substring-befor

Subject: in this xsl , why dont get result with substring-before ..
From: henry human <henry_human@xxxxxxxx>
Date: Fri, 25 Mar 2005 14:37:52 +0100 (CET)
substring befor
Problem number 1)i have this two files. when i try to
get with substring-before or substring-after i get no
data
Problem number 2) 
why i get in this for-each loop only one
time the content of workstep1 node 
Problem number 3) 
what is the other alternativity to call a template
in this loop instead of to use xsl:apply-templates ? 
thanks


<?xml version='1.0'?> 
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="html"/> 
<xsl:template match="/Job">
<html><head><META http-equiv="Content-Type"
content="text/html; charset=iso-8859-1"/>

</head><body>

<table>
<tr> 
   <td></td>    <td> <b>JOB Desc. </b></td></tr> 

<xsl:for-each select="Jobsdetails"> 
<tr> 
   <td></td>
       <td>  <xsl:value-of
select="jobDescription"/></td>
       
 </tr>

<xsl:apply-templates select="worksPart1"/>
</xsl:for-each>
</table></body></html>

</xsl:template>


<xsl:template match="worksPart1" >
<tr> <td></td>
   <td>
    <xsl:if test="contains(bbb,'RRR')">
    <xsl:value-of
select="substring-before('bbb','RRR')"/>
    +<xsl:value-of
select="substring-after('bbb','RRR')"/>
    </xsl:if>
       </td>    
       
 </tr>

</xsl:template>
</xsl:stylesheet>


------------------------------------------
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<Job>


<Jobsdetails>
<jobDescription>mydescription</jobDescription>
<worksPart1>

<bbb>beforeRRRafter</bbb>
<worksNr>20362</worksNr>

</worksPart1>
</Jobsdetails>
</Job>




	

	
		
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