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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Accessing immediate parent node in XSL
On Wed, Mar 16, 2005 at 10:48:37PM -0800, Arulraj wrote: > Hi all, > > I have need some XPath way to access the attribute. > I am having the following XML structure. > > <?xml version="1.0" encoding="UTF-8"?> > <Layout> > <Box name="toolbar" position="absolute" top="37px" > left="0px" width="797px" height="26px" z-index="7" > background-color="transparent"> > .................... > </Box> > <Box name="applicationframe" position="absolute" > top="63px" left="0px" width="797px" height="504px" > z-index="16"> > <Box name="rowlist" type="list" top="44px" left="11px" > width="763px" height="24px" z-index="17" > background-color="transparent"> > ....................... > </Box> > </Box> > </Layout> > > In my XSL, > > <xsl:template match="Box" mode="list"> > ...... > </xsl:template> > The above template access Box with a name="rowlist" > from here i want to access immediate parent node i.e > widht and height of applicationframe Box. Could do parent::Box[@name='applicationframe']/width or more generally ancestor::Box[@name='applicationframe']/@width if you are nested more deeply.... > > pls help me > Thanks > Regards, > Arul > > > > > __________________________________ > Do you Yahoo!? > Make Yahoo! your home page > http://www.yahoo.com/r/hs
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