Re: Replacing strings in XSL

When I see my below post in my browser (IE 6), I
cannot see the 3rd argument of translate function to
what I wrote. It appears as a blank(its a expected
browser function), and not the character reference I
wrote (160; preceded by &#). I guess you would also
see it as space .. I thought of pointing this to you.

You may look at "HTML source" of this post to see
exactly what I wrote!

I would also recommend this link..
http://www.dpawson.co.uk/xsl/sect2/nbsp.html
to read more about nbsp.

Regards,
Mukul

--- Mukul Gandhi <mukul_gandhi@xxxxxxxxx> wrote:
> This can be achieved with the translate function..
> 
> For e.g. if the XML is -
> <?xml version="1.0" encoding="UTF-8"?>
> <root>
>   <MANUFACTURER>LG Electronics Inc</MANUFACTURER>
> </root>
> 
> and XSL is -
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>   
>   <xsl:output method="html" indent="yes" />
>   
>   <xsl:template match="/root">  
>     <p><xsl:value-of
> select="translate(MANUFACTURER,'
> ', 'B ')" /></p>
>   </xsl:template>
>   
> </xsl:stylesheet>
> 
> The output of transform is -
> <p>LG&nbsp;Electronics&nbsp;Inc</p>
> 
> Hope this is what you needed.
> 
> Regards,
> Mukul



		
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