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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Common Element Solution (XSL 2.0)
> That last line has me puzzled Mike. Would someone expand
please, for
> the uninitiated?
In the input we have a set of tables each containing zero
or more columns, each column has a name. We want to find
the names of the columns that appear in each table. Group
the columns by name; for each group (of columns with the
same name), the column appears in every table if the number
of tables containing a column in that group equals the
total number of tables.
Any clearer?
<tables>
<table name="table1">
<column name="col1"/>
<column name="col2"/>
<column name="col3"/>
<column name="col4"/>
</table>
<table name="table2">
<column name="col1"/>
<column name="col2"/>
<column name="col5"/>
<column name="col6"/>
</table>
Yes, the basics are clear. Your last line(s) were
you want something like
count(current-group()/parent::table) = $number-of-tables
relying on the fact that "/" eliminates duplicates.
My question was, how does the '/' eliminate duplicates?
That's the bit I don't understand.
regards DaveP
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