Newbie question - Muenchian method and XPath
Sorry, I'm relatively new to XSLT - so it's another Muenchian Method/XPath query I'm afraid!
I have an XML file, similar to... (obviously this isn't my real data, nor real tag names...)
<group value="1"> <item type="a" name="apple" /> <item type="a" name="banana" /> <item type="c" name="carrot" /> </group> <group value="2"> <item type="b" name="some" /> <item type="c" name="random" /> <item type="c" name="words" /> </group>
... and yes, I want to do grouping with XSLT 1.0.
I'm using an <xsl:template match="group"> and then the code from Jeni's page (http://www.jenitennison.com/xslt/grouping/muenchian.html) in there, but the output is sort of like:
"Group 1 ======== a - apple, banana c - carrot, random, words
Group 2 ======== b - some"
So it's dragging all <item>s together (as xsl:key is obviously document wide and I can't use scope)., which isn't what I want! (I want:
"Group 1 ========== a - apple, banana c - carrot
Group 2 ======== b - some c - random, words"
I've tried amending one line of the solution to:
<xsl:for-each select="item[(../@value='1') and (count(. | key('mykey', @type)) = 1)]">
just to see if I can get ONLY results for group 1 which are meant to be in group 1, but even this isn't working...
I presume I've just been a bit naive with my XPath expression - could anyone explain how best to tackle this?
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