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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Return ancestor siblings based on Id
Hi guys,
Another chapter in this tragedy.
Question:
The expression '//tree_node[@id=9]/ancestor::tree_node' returns a nodeset
containing node with id(7). I have verified this with xpath visualizer.
How do I return the ALL siblings of this node also.
The result being
Node(id=7)
Node(id=8) : sibling of Node(id=7)
Node(id=9) : sibling of Node(id=7)
Node(id=14) : sibling of Node(id=7)
HELP APPRECIATED!!!!
ALL TO0 FAMILIAR XML STRUCTURE:
<tree>
<tree_node id="7" value="Test Level One A">
<tree_node id="8" value="Test Level Two A"/>
<tree_node id="9" value="Test Level Two B">
<tree_node id="11" value="Test Level Three B"/>
<tree_node id="10" value="Test Level Three A">
<tree_node id="12" value="Test Level Four A"/>
<tree_node id="13" value="Test Level Four B"/>
</tree_node>
</tree_node>
<tree_node id="14" value="Test Level Two C"/>
</tree_node>
</tree>
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