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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] AW: Is conditional group-by possible?
As far as I can tell, you don't have any FED_ID_FLAG, FED_ID or SOC_SEC_ID elements in your input document. You missed the "PROV_" and "PROS_" part your element names.... HTH wbr, Roman _______________________________________ Roman Huditsch IT and Electronic Publishing LexisNexis ARD Orac Marxergasse 25 1030 Vienna Austria ph: +43-1-534 52-1514 f: +43-1-534 52-140 e-mail roman.huditsch@xxxxxxxxxxxxx www.lexisnexis.at > -----Urspr|ngliche Nachricht----- > Von: Jim Neff [mailto:jneff@xxxxxxxxxxxxxxx] > Gesendet: Dienstag, 25. Januar 2005 16:52 > An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Betreff: Is conditional group-by possible? > > Greetings, > > Is a conditional group-by possible? > > Here is what I tried: > > <xsl:for-each-group > select="Table" > group-by="(if ((FED_ID_FLAG = 'F') > and (not(FED_ID = ''))) > then FED_ID > else SOC_SEC_ID)"> > > And I get nothing in my output. > > My input looks like simliar to this : > > <NewDataSet> > <Table> > <PROV_SOC_SEC_ID>111104550</PROV_SOC_SEC_ID> > <PLOS_FED_ID_FLAG>S</PLOS_FED_ID_FLAG> > <PLOS_FED_ID>190404550</PLOS_FED_ID> > <PATIENT_LAST_NAME>Doe</PATIENT_LAST_NAME> > <PATIENT_FIRST_NAME>John</PATIENT_FIRST_NAME> > </Table> > <Table> > <PROV_SOC_SEC_ID>111104550</PROV_SOC_SEC_ID> > <PLOS_FED_ID_FLAG>S</PLOS_FED_ID_FLAG> > <PLOS_FED_ID>190404550</PLOS_FED_ID> > <PATIENT_LAST_NAME>Doe</PATIENT_LAST_NAME> > <PATIENT_FIRST_NAME>Jane</PATIENT_FIRST_NAME> > </Table> > <Table> > <PROV_SOC_SEC_ID>777104550</PROV_SOC_SEC_ID> > <PLOS_FED_ID_FLAG>F</PLOS_FED_ID_FLAG> > <PLOS_FED_ID>880121550</PLOS_FED_ID> > <PATIENT_LAST_NAME>Smith</PATIENT_LAST_NAME> > <PATIENT_FIRST_NAME>Mary</PATIENT_FIRST_NAME> > </Table> > </NewDataSet> > > This should result in two groups, one 111104550, the other 880121550. > > What I want is to use the FED_ID element to group by if the > FED_ID_FLAG = 'F' and FED_ID is an empty string. Otherwise I > want to use the SOC_SEC_ID element to group. > > Thanks in advance, > Jim Neff
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