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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: accessing parent element in if clause
If you just wanted to match the node which has the definition as a parent, you could do with <xsl:template match="node[parent::definition]"> I assumed that 'node' is a physical node in your XML ...or did you mean node() to say any node which has a parent called definition?? HTH vasu ----- Original Message ----- From: "Rahil Qamar Yahoo" <qamar_rahil@xxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, January 20, 2005 12:01 PM Subject: accessing parent element in if clause > Hi > > Im sure its a fairly basic question for most but Im just starting out on > XSLT and cant find any resources to solve my problem. > > I want to perform an operation based on an 'if' clause as shown below > > ----------------------------------- > <xsl:template match="/"> > <PrimeConcept><xsl:apply-templates select="/archetype/definition/node"/> > </PrimeConcept> > </xsl:template> > > <xsl:template match="node"> > <xsl:if test="parent::node()=definition"> > <xsl:attribute name="id"><xsl:value-of > select="@id"/></xsl:attribute> > <xsl:attribute name="type"><xsl:value-of > select="@rm_class"/></xsl:attribute> > </xsl:if> > </xsl:template> > ---------------------------------- > > Theres a problem with the <xsl:if> statement where Im trying to > determine whether the <node> element is the child of the <definition> > element. I think theres a problem in the way Im trying to access the > parent node but cant figure out the right way. > > Could someone please help. > > Thanks > Rahil
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