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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Counting level of nodes beneath current (in XPATH)
Hi again,
I will try if this example explains it better... With the example XML: <X>
<Y>
<Z>lv 1 (one lv. descendants)</Z>
<X>
<Y>
<Z>lv 2 (zero lv. descendants)</</Z>
</Y>
</X>
</Y>
<Y>
<Z>lv 1 (two lv. descendants)</</Z>
<X>
<Y>
<Z>lv 2 (one lv. descendants)</</Z>
<X>
<Y>
<Z>lv 3 (zero lv. descendants)</Z>
</Y>
</X>
</Y>
<Y>
<Z>lv 2 (two lv. descendant)</Z>
<X>
<Y>
<Z>lv 3 (zero lv. descendant)</Z>
</Y>
</X>
<X>
<Y>
<Z>lv 3 (one lv. descendants)</Z>
<X>
<Y>
<Z>lv 4 (zero lv. descendants)</Z>
</Y>
<Y>
<Z>lv 4 (zero lv. descendants)</Z>
</Y>
</X>
</Y>
</X>
</Y>
</X>
</Y>
</X>With a parameter $lv="2", and an id-transformation, I should get the xml without (zero lv. descendants) and (one lv. descendants), that is: <X>
<Y>
<Z>lv 1 (two lv. descendants)</</Z>
<X>
<Y>
<Z>lv 2 (two lv. descendant)</Z>
</X>
</Y>
</X>With $lv="1" I should get all except (zero lv. descendatnts), that is, without leaf Y-nodes (and without the X-node containing the leaf Y-nodes): <X>
<Y>
<Z>lv 1 (one lv. descendants)</Z>
</Y>
<Y>
<Z>lv 1 (two lv. descendants)</</Z>
<X>
<Y>
<Z>lv 2 (one lv. descendants)</</Z>
</Y>
<Y>
<Z>lv 2 (two lv. descendant)</Z>
<X>
<Y>
<Z>lv 3 (one lv. descendants)</Z>
</Y>
</X>
</Y>
</X>
</Y>
</X>So in all, instead of wanting, say the first two levels of Y-nodes, instead I want all the nodes top-down, except for ie. buttom 2 levels. I would be happy if I, from a given node, could count how many levels of Y-nodes where below the current. I do not know if that was the answer that David Carlisle gave, I did not understand the answer that well (which is fair enough given that my question was perhaps not understood :-) ) I hope that with this, my question is clear, and that an XPath solution is possible. Regards, Ragulf Pickaxe :-) _________________________________________________________________ FREE pop-up blocking with the new MSN Toolbar - get it now! http://toolbar.msn.click-url.com/go/onm00200415ave/direct/01/
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