Re: Best way to count siblings

  <xsl:value-of select="count(preceding-sibling::* | following-sibling::*)"/>

count(../*) -1 is shorter, you;d have to ask an implementer which is
more efficient. Often the siblings are the current node list in which
case last()-1 is likely to be the most efficient.

David

________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________