Re: Best way to count siblings
<xsl:value-of select="count(preceding-sibling::* | following-sibling::*)"/> count(../*) -1 is shorter, you;d have to ask an implementer which is more efficient. Often the siblings are the current node list in which case last()-1 is likely to be the most efficient. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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