Counting sub-nodes per page in xsl with custom paging

Hey everyone,

This is the first time that I am posting to the xsl list and I am
pretty new to xsl. 

I would appreciate any help that you can provide with an issue I am
having.

I am generating a potentially multi-page html document.
I have the issue of repeating the header and footer worked out.
I can only display a certain number, (15), of sample nodes per page,
so when the sample node position/ 15 is greater than 1, 2, etc. I
insert the header again. Example xml and xsl is below.
  
  <sample>
              <container></container> 
              <container></container> 
              <container></container> 
              <container></container> 
  </sample>
  <sample>
              <container></container> 
              <container></container> 
  </sample>
  <sample>
              <container></container> 
  </sample>
  <sample>
              <container></container> 
              <container></container> 
              <container></container> 
  </sample>
   
              <xsl:template name="pageNumber">
                          
                          <xsl:choose>
                                      <xsl:when test="position() mod
15 =0">
                                                 
 <xsl:value-ofselect="round(position() div 15 + 1)"/>
                                      </xsl:when>
                                      <xsl:otherwise>
                                                  <xsl:value-of
 select="round(position() div 15 + 1)"/>
                                      </xsl:otherwise>            
                          </xsl:choose>
              </xsl:template>
   
   
I have been able to generate a page number such as "page 1 of 2",also
using this technique.
   
The problem I have not been able to figure out that I want to count
and display how many container nodes exist on a specific page, for
example "# of containers for this page = 25".
  
Any ideas on how I might do this?
  
Thanks,
   
Tony DiSalvo