RE: Re: Problem passing node-set to params (RTF)
> But, I fixed my problem. I was using two different > variable names. So in my template I did this: > > <xsl:template name="foo"> > <xsl:param name="srcNode"/> > <xsl:param name="destNode"/> > </xsl:template> > > And in my calls I was doing this: > > <xsl:call-template name="foo"> > <xsl:with-param name="src" select="current()"/> > <xsl:with-param name="dest" select="$local"/> </xsl:call-template> Oops, and I actually saw that typo. Next time I won't assume that it was just a typo in the email! Or at least I should consider that that might be what's causing the problem. Yeah, it makes perfect sense now. The default value of a parameter that has no explicit default value specified is the empty string "", which of course can't be converted to a node-set. Evan
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