RE: Problem passing node-set to params (RTF)
Hi Charlie, It shouldn't matter whether you use a variable reference or expression, provided that the variable was declared using the "select" attribute. The only time RTFs are created is when you use <xsl:variable>, etc. with *content* rather than the "select" attribute. What XSLT processor are you using? And what is the undesired behavior? An error message? Evan > I'm having trouble passing a node-set as a parameter. > I'm trying to reduce the size of my XSL so its more > managable and easier to modify. So I've taken a > section of code that was repeated over my XSL and > turned it into a template with parameters. I'm trying > to use call-template to pass in the parameters, but my > srcNode and destNode parameters are turning into > Result Tree Fragments. After reading the FAQ it said > that assigning existing variables to parameters turns > them into RTF. But, when I tried replacing them with > expressions rather than $var it still ended up a RTF. > What do I have to do to use node-sets? > > Here is a quick example of what I'm doing. I've also > tried replacing $local with the XPATH expression, but > I still get a RTF. > > <xsl:variable name="local" > select="../member[@component=$localComponent]"/> > <xsl:call-template name="insertAccessRule"> > <xsl:with-param name="guid" select="current()/access/@guid0"/> > <xsl:with-param name="agent" > select="current()/@agent-ip"/> > <xsl:with-param name="src" select="current()"/> > <xsl:with-param name="dest" select="$local"/> </xsl:call-template> > > <xsl:template name="insertAccessRule"> > <xsl:param name="guid"/> > <xsl:param name="agent"/> > <xsl:param name="srcNode"/> > <xsl:param name="destNode"/> > .... > </xsl:template> > > Thanks > Charlie
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